Given points A(-2,-3) B (2,5) C (-1,0). Find equation of line parallel to AB & passing thru pt (3,10) plz help

I'm really not sure what to do here. I've tried diff things pt slope form but idk i just cant seem to figure it out ! I'm confused If anyone could help that'd be so great :D








The rest of the questions are:





FInd the equation of the line that passes through A and C.





And then,





Find the equation of the line that passes through B and C.





You don't have to give me the answer necessarily, just if anyone is good with math and can kind of explain how to do this I'd really appreciate it...








Math has never seemed to click with me. I've done this before %26amp; I ended up forgetting how to do it now !








Ty

Given points A(-2,-3) B (2,5) C (-1,0). Find equation of line parallel to AB %26amp; passing thru pt (3,10) plz help
First find the slope of AB


slope = rise / run = (5- (-3)) / (2- (-2)) = (5+3)/ (2+2) = 8/4 = 2


The line parallel to AB should have the same slope, 2.





Then use the equation y=mx + b, where m is slope and b is the y intercept, and plug in the slope, and coordinates you have:


y = mx + b


10 = (2*3) + b


10 = 6 +b


10 - 6 = 6 - 6 +b


4 = b





Now you have your y-intercept and slope





So the equation should be:


y = 2x + 4





Follow the same logic for the remaining parts of the question


So, find the slope for AC, then plug the slope into the y=mx+b equation with the (3,10) coordinates to find the y-intercept. Then plug the slope and y-intercept into the y=mx+b equation.





Then, find the slope for BC, plug that slope into the y=mx+b equation with the (3,10) coordinates to find that y-intercept. Then plug the slope and y-intercept into the y=mx+b equation.
Reply:I'll tell u how to do the first question. If the line u want is parallel to line AB, then it must have the same slope as line AB; which is m in the equation y=mx+b. And, since is passes through point (3,10), you can use that point as the x and y in the equation of the line y=mx+b. So, your overall equation for the line in question is 10=2(3)+b. You solve for b, the y-intercept, which equals 4. So, the equation of the line is y=2x+4. Hope that helps.
Reply:First you have to find the slope of AB: -3 - 5= -8 -2 - 2= -4 -8/-4= 2, so your slope of the line is 2. Next you have to find the y-intercept of the line that passes through (3,10). You do this using the slope. Every time the x-value decreases by 1 the y-value decreases by 2, so when x=0 y=4 because 10-6=4. The equation for this line is y=2x+4.