Rearranging equations? c=4y-ay t^2=(4r+5q)/r Please help.?

I am stuck with these two equations as to how to rearrange them so that :





y is the subject of c=4y-ay





r is the subject of t^2= (4r+5q)/r





Any help will be greatly appreciated. Thanks

Rearranging equations? c=4y-ay t^2=(4r+5q)/r Please help.?
c=4y-ay=y(4-a)


=%26gt; y = c/(4-a)





t^2= (4r+5q)/r = 4 + 5q/r


=%26gt; r = 5q/(t^2-4)
Reply:Good day sir!


c=4y-ay


c=y(4-a)


Divide both sides by (4-a)


c/(4-a) =y





t^2=(4r+5q)/r


Multiply both sides by r


(r)t^2=(4r+5q)


Remove brackets (they no longer serve any purpose)


rt^2=4r+5q


Subtract 4r from both sides


rt^2-4r=4r-4r+5q


rt^2-4r=5q


Factor


r(t^2-4)=5q


Divide both sides by (t^2-4)


r=5q/(t^2-4)
Reply:Ok... so basically it goes like this:





c=4y-ay the 4y-ay has a factor, y, you can take out


c=y(4-a) Divide by (4-a)on both sides to get the y alone


y=c/(4-a)








t^2=(4r+5q)/r Divide out (4r+5q)/r





t^2=4+(5q)/r subtract 4 from both sides


t^2-4=(5q)/r Cross muliply





(t^2-4)r=5q Divide both sides by t^2-4 to get r alone





r=5q/(t^2-4)
Reply:1)y=c/(4-a)


2)r=5q/(t^2-4)